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NEW QUESTION: 1
Refer to the exhibit.

All of the routers on this network are running RIP. If you edit the R3 RIP process configuration to reduce the number of hops from R3 to R1, which statement about the configuration change is true?
A. Configuring no passive-interface for GigabitEthernet0/0 in the R3 RIP process reduces the number of hops to R1 by 1.
B. Configuring no passive-interface for GigabitEthernet0/1 in the R3 RIP process reduces the number of hops to R1 by 1.
C. Configuring no passive-interface for GigabitEthernet0/0 in the R3 RIP process reduces the number of hops to R1 by 2.
D. Configuring no passive-interface for GigabitEthernet0/1 in the R3 RIP process reduces the number of hops to R1 by 3.
Answer: C
Explanation:
By changing the link from R3 to R2 to not be passive, traffic can then take the direct route from R3-R2-R1 instead of the longer path of R3-R6-R5-R4-R1, resulting in two less hops.

NEW QUESTION: 2
Which configuration can be used for enabling Coherence as an L2 Cache?
@Entity
A. @CacheInterceptor (CoherenceInterceptor.class)
public class Employee implements Serializable
B. @Customizer(CoherenceReadWriteCustomizer.class)
public class Employee implements Serializable
@Entity
C. @CacheInterceptor (CoherenceReadCustomizer.class)
public class Employee implements Serializable
@Entity
D. @Customizer(CoherenceReadCustomizer.class)
public class Employee implements Serializable
@Entity
Answer: A
Explanation:
Explanation/Reference:
Reference: http://www.oracle.com/technetwork/middleware/ias/index-096228.html

NEW QUESTION: 3
以下の展示に示すように、Dynamics 365インスタンスを管理します。

EMEAを新しい実稼働インスタンスとして構成します。 EMEAインスタンスは、北米インスタンスと同じ構成を使用する必要があります。 EMEAインスタンスには、北米のデータを含めないでください。
Dynamics 365管理センターを使用して、EMEAインスタンスを構成する必要があります。
順番に実行する必要がある3つのアクションはどれですか？回答するには、適切なアクションをアクションのリストから回答エリアに移動し、正しい順序に並べます。

Answer:
Explanation:

Explanation

References:
https://docs.microsoft.com/en-us/dynamics365/customer-engagement/admin/copy-instance

NEW QUESTION: 4
Given:

Which code fragment, when inserted at line 14, enables the code to print Mike Found?
A. patient p = new Patient ("Mike");
int f = pas.indexOf(P)
B. int f = ps.indexOf {new patient ("Mike")};
C. int f = ps.indexOf(p2);
D. int f = ps.indexOf (patient("Mike"));
Answer: A

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