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NEW QUESTION: 1
Scenario:
あなたはSWITCH.comで働いています。 彼らは、トポロジダイアグラムに示すように、既存のネットワークに新しいスイッチ（SwitchB）を追加しました。
RouterAは現在正しく設定されており、SwitchAおよびSwitchB上のデバイスにルーティング機能を提供しています。 SwitchAは現在正しく設定されていますが、SwitchBの追加をサポートするように変更する必要があります。 SwitchBは最小構成です。 SwitchAとSwitchBの必要な設定と競合することを任されています。 SwitchAとSwitchBは、イネーブルパスワードとしてシスコを使用します。
SwitchAの構成要件
SwitchAのVTPおよびSTPコンフィギュレーションモードは変更しないでください。
* SwitchAは、VLAN 11,12,13,21,22,23のルートスイッチである必要があります。他のVLANはすべてデフォルト値のままにしておきます。
SwitchBの構成要件
* Vlan 21
* Name: Marketing
* will support two servers attached to fa0/9 and fa0/10
* Vlan 22
* Name: Sales
* will support two servers attached to fa0/13 and fa0/14
* Vlan 23
o Name: Engineering
o will support two servers attached to fa0/15 and fa0/16
* サーバに接続するアクセスポートは、デバイスの接続を検出するとただちに転送状態に移行する必要があります。
* スイッチのVTPモードはスイッチと同じである必要があります。
* スイッチはSwitchと同じスパニングツリーモードで動作する必要があります
* スイッチでルーティングを設定する必要はありません
* SVI vlan 1のみが設定され、アドレス192.168.1.11/24を使用します。スイッチ間の接続設定要件
* 運用上およびセキュリティ上の理由から、トランキングは無条件であり、トランクリンクをトラバースするときはVlans 1,21,22,23にタグを付ける必要があります。
* SwitchAとSwitchBの間の2つのトランクは、すべてのVLANに帯域幅を最大限に活用できるモードで設定する必要があります。 このモードは、SwitchAがアクティブ化を制御している非独自仕様のプロトコルで行う必要があります。
* 不要なブロードキャストの伝播は、このトランクリンク上の手動プルーニングを使用して制限する必要があります。

Answer:
Explanation:
Here are steps:
hostname SWITCH_B
!
!
vlan 21
name Marketing
vlan 22
name Sales
vlan 23
name Engineering
!
!
interface FastEthernet0/3
switchport trunk allowed vlan 1,21-23
channel-protocol lacp
channel-group 1 mode passive
switchport mode trunk
!
interface FastEthernet0/4
switchport trunk allowed vlan 1,21-23
channel-protocol lacp
channel-group 1 mode passive
switchport mode trunk
!
interface FastEthernet0/9
switchport access vlan 21
switchport mode access
spanning-tree portfast
!
interface FastEthernet0/10
switchport access vlan 21
switchport mode access
spanning-tree portfast
!
interface FastEthernet0/13
switchport access vlan 22
switchport mode access
spanning-tree portfast
!
!
interface FastEthernet0/14
switchport access vlan 22
switchport mode access
spanning-tree portfast
!
interface FastEthernet0/15
switchport access vlan 23
switchport mode access
spanning-tree portfast
!
interface FastEthernet0/16
switchport access vlan 23
switchport mode access
spanning-tree portfast
!
!
interface GigabitEthernet1/1
!
interface GigabitEthernet1/2
!
interface Port-channel 1
switchport mode trunk
switchport trunk encapsulation dot1q
spanning-tree allowed vlans 1,21-23
!
interface Vlan1
ip address 192.168.1.11 255.255.255.0
!
end
SWITCH_B(config)#
hostname SWITCH_A
!
panning-tree vlan 11 root primary
spanning-tree vlan 12 root primary
spanning-tree vlan 13 root primary
spanning-tree vlan 21 root primary
spanning-tree vlan 22 root primary
spanning-tree vlan 23 root primary
!
interface FastEthernet0/3
switchport trunk allowed vlan 1,21-23
channel-protocol lacp
channel-group 1 mode active
switchport mode trunk
!
interface FastEthernet0/4
switchport trunk allowed vlan 1,21-23
channel-protocol lacp
channel-group 1 mode active
switchport mode trunk
!
interface FastEthernet0/21
switchport access vlan 21
switchport mode access
!
interface FastEthernet0/22
switchport access vlan 22
switchport mode access
!
interface FastEthernet0/23
switchport access vlan 23
switchport mode access
!
interface GigabitEthernet1/1
!
interface GigabitEthernet1/2
!
interface Port-channel 1
!
interface Vlan1
no ip address
shutdown
!
ip default-gateway 192.168.1.1
!
!
End

NEW QUESTION: 2
A company firewall engineer has configured a new DMZ to allow public systems to be located away from the internal network. The engineer has three security zones set:

The engineer wants to configure remote desktop access from a fixed IP on the remote network to a remote desktop server in the DMZ. Which rule would best fit this requirement?
A. Permit 217.77.88.0/24 11.12.13.50 RDP 3389
B. Permit 217.77.88.12 11.12.13.50 RDP 3389
C. Permit 217.77.88.0/24 11.12.13.0/24 RDP 3389
D. Permit 217.77.88.12 11.12.13.0/24 RDP 3389
Answer: B

NEW QUESTION: 3
PPP Maximum Receive Unit (Maximum Receive Unit, MRU) is the default number of bytes ().
A. 0
B. 1
C. 2
D. 3
Answer: D

NEW QUESTION: 4



A. public class deep extends Deeper {
public Long getDepth (int d) {
return 5L;
}}
B. public class deep extends Deeper {
public Double getDepth() {
return 5d;
}}
C. public class deep extends Deeper {
public String getDepth () {
}}
D. public class deep extends Deeper {
public Short getDepth () {
return 5;
}}
E. public class deep extends Deeper {
protected Integer getDepth(){
return 5;
}}
Answer: D,E
Explanation:
Note: The abstract class Number is the superclass of classes Byte, Double, Float, Integer, Long, and Short.
Subclasses of Number must provide methods to convert the represented numeric value to byte, double, float, int, long, and short.
When class C extends B, we say that C is a "subclass" of B, and B is the "superclass" of C.
This is called inheritence, because C inherited from B.

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