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NEW QUESTION: 1



A. 192.168.25.28 255.255.255.240
B. 192.168.25.16 255.255.255.252
C. 192.168.25.16 255.255.255.240
D. 192.168.25.28 255.255.255.252
E. 192.168.25.0 255.255.255.240
F. 192.168.25.0 255.255.255.252
Answer: C
Explanation:
The binary version of 20 is 10100.
The binary version of 16 is 10000.
The binary version of 24 is 11000.
The binary version of 28 is 11100.
The subnet mask is /28. The mask is 255.255.255.240.
Note:
From the output above, EIGRP learned 4 routes and we need to find out the summary of them:
+
192.168.25.16
+
192.168.25.20
+
192.168.25.24
+
192.168.25.28 -> The increment should bE. 28 - 16 = 12 but 12 is not an exponentiation of 2 so we must choose 16 (24). Therefore the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) =
255.255.255.240
So the best answer should be 192.168.25.16 255.255.255.240

NEW QUESTION: 2
What is the mechanism could be used to avoid the problem of TCP Starvation / UDP Dominance?
A. Place UDP traffic in a dedicated traffic-class with the bandwidth keyword configured
B. Configure QoS to police UDP traffic to the desired volume
C. WRED to balance TCP and UDP utilization
D. Use policy routing to send the UDP and TCP traffic over different paths
Answer: C

NEW QUESTION: 3

A. Option C
B. Option B
C. Option A
D. Option D
Answer: C

NEW QUESTION: 4
Refer to the exhibit. R3 is failing to join the multicast group 224.1.1.1 that is sourcing from R1. Which two actions can you take to allow multicast traffic to flow correctly? (Choose two.)
A. Configure OSPF on R1 and R3 to include the tunnel interfaces.
B. Add an additional static multicast route on R2 for multicast group 224.1.1.1 toward R3.
C. Add an additional static unicast route on R2 toward the loopback interface of R3.
D. Remove the static unicast route on R1.
E. Remove the static multicast route on R1.
F. Replace the static multicast route on R1 to send traffic toward R2.
Answer: A,E

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