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NEW QUESTION: 1
What is the purpose of a glossary?
A. Establish common vocabulary
B. Establish a common vision
C. Define universal constraints
D. Establish testable requirements
Answer: A

NEW QUESTION: 2


A. Option B
B. Option C
C. Option D
D. Option A
E. Option E
Answer: A,D

NEW QUESTION: 3
RTA is a leaf router that directly connects to host A through interface GigabitEthernet 1/0/0. The interface is configured as follows:
interface Ethernet1/0/0
undo shutdown
ip address 192.168.4.2 255.255.255.0
pim sm
igmp enable
igmp version 3
igmp ssm-mapping enable
Configurations in the IGMP view are as follows:
igmp
ssm-mapping 233.1.1.0 255.255.255.0 10.10.1.1
A user sends an IGMPv2 Report message on host A to join groups 232.1.1.1 and 233.1.1.1 but the user cannot receive (10.10.1.1, 232.1.1.1) and (10.10.1.1, 233.1.1.1) messages. To solve this problem, which of the following configurations are required?
A. Configure ssm-policy in the PIM view and use the ACL to set the SSM group address range to 232.1.1.1 and 233.1.1.1.
B. Configure ssm-policy in the PIM view and use the ACL to set the SSM group address range to 233.1.1.1.
C. Configure ssm-mapping 232.1.1.0 255.255.255.0 10.10.1.1 in the IGMP view.
D. Configure ssm-policy in the PIM view and use the ACL to set the SSM group address range to 232.1.1.1.
Answer: A,C

NEW QUESTION: 4



A. RoleName
B. SELECT R.RoleName, ISNULL (U.ActiveUserCount,0) AS ActiveUserCountFROM tblRoles R LEFT JOIN (SELECT RoleId, COUNT(*) AS ActiveUserCountFROM tblUsers WHERE IsActive = 1 GROUP BY R.RoleId) U
C. SELECT R.RoleName, U.ActiveUserCount FROM tblRoles R CROSS JOIN(SELECT RoleId, COUNT(*) AS ActiveUserCountFROM tblUsers WHERE IsActive = 1 GROUP BY R.RoleId) U
D. SELECT R.RoleName, COUNT(*) AS ActiveUserCount FROM tblRoles RCROSS JOIN (SELECT UserId, RoleId FROM tblUsers WHERE IsActive = 1) UWHERE U.RoleId = R.RoleIdGROUP BY R.RoleId,
E. SELECT R.RoleName, COUNT(*) AS ActiveUserCount FROM tblRoles RLEFT JOIN (SELECT UserId, RoleId FROM tblUsers WHERE IsActive = 1) UON U.RoleId = R.RoleIdGROUP BY R.RoleId, R.RoleName
Answer: E

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