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NEW QUESTION: 1
Examine this query:
SELECT 2 FROM dual d1 CROSS JOIN dual d2 CROSS JOIN dual d3;
What is returned upon execution?
A. an error
B. 0 rows
C. 6 rows
D. 1 row
E. 8 rows
F. 3 rows
Answer: D
NEW QUESTION: 2
Which of the following is NOT a factor that is part of a firewall configuration?
A. Encryption
B. Source IP
C. Protocol
D. Port
Answer: A
Explanation:
Firewalls take into account source IP, destination IP, the port the traffic is using, as well as the network protocol (UDP/TCP). Whether or not the traffic is encrypted is not something a firewall is concerned with.
NEW QUESTION: 3
Hong Kong prospered as the center of trade with China, _______ until it fell to the Japanese in 1941.
A. flourishing
B. increasing
C. succeeding
D. retreating
E. languishing
Answer: A
Explanation:
Explanation/Reference:
Explanation:
In this sentence, the missing word should continue in the same direction as the first. You're looking for a word that is consistent with and that complements prospered. You can easily eliminate choices C and (D), both of which contradict the first clause. (Languish means "weaken.") Choice A makes for a vague sentence: What was Hong Kong increasing? Choice B also makes for a vague sentence: What was Hong Kong succeeding in? That leaves choice (E).Flourishing means "thriving or growing" - a good complement to the idea of prospering. So choice E provides the best completion.
NEW QUESTION: 4
A. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo
B. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo
C. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
F. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
G. CustNoWHERE D.CustNo IS NULL
H. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
I. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
J. CustNo
Answer: F
Explanation:
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name ;
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx
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