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NEW QUESTION: 1

A. S/MIME
B. PGP
C. SYSLOG
D. RSH
E. SNMPv3
Answer: E
Explanation:
Explanation
The network monitoring need to use a network management protocol. SNMP has become the de facto standard of network management protocols. The securityweaknesses of SNMPv1 and SNMPv2c are addressed in SNMPv3.

NEW QUESTION: 2
A financial service company is running distributed computing software to manage a fleet of 20 servers for their calculations. There are 2 control nodes and 18 worker nodes to run the calculations. Worker nodes can be automatically started by the control nodes when required. Currently, all nodes are running on demand, and the worker nodes are uses for approximately 4 hours each day.
Which combination of actions will be most cost-effective? (Select Two)
A. Use reserved instances for the control nodes.
B. Use spot instances for the control nodes and On-demand instances if there is no Spot availability.
C. Use dedicated Hosts for the control nodes.
D. Use spot instances for the worker nodes and On-demand instances if there is no spot availability.
E. Use reserved instances for the worker nodes.
Answer: A,D

NEW QUESTION: 3
Which of the following technologies enables port sharing on a single physical port?
A. WWNN
B. Port mapping
C. WWPN
D. NPIV
Answer: D
Explanation:
Explanation/Reference:
Reference: https://pubs.vmware.com/vsphere-4-esx-vcenter/index.jsp?topic=/ com.vmware.vsphere.vmadmin.doc_41/vsp_vm_guide/configuring_virtual_machines/ t_configure_fibre_channel_npiv_settings.html

NEW QUESTION: 4
If the sum of six numbers is between 135 and 164, then the average (arithmetic mean) of the six numbers could be which of the following?
A. 31.25.
B. 25.5.
C. 20.5.
D. 15.4.
E. 32.5.
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Define X as the sum of all the six numbers, 135 < X < 164.
The average of the six numbers, using the average formula, is X/6.
Divide both sided of the equation by 6: 135/6 < X/6 < 164/6 22.5 < X/6 < 27.33.
The average has to be in that range and therefore the only answer could be C.

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