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NEW QUESTION: 1
The Show in Catalog flag for one of your customer's items is currently set to "No". The customer would
like to change this flag to "Yes".
Which of the following workflow combinations are required to update this flag?
Please choose the correct answer.
Response:
A. - Search Master Inventory
- View Master Inventory
- Edit Master Inventory
B. - Search Scheduled Offering Catalog
- View Scheduled Offering Catalog
- Edit Scheduled Offering Catalog
C. - Search Catalog
- View Catalog
- Edit Catalog
D. - Search Item Catalog
- View Item Catalog
- Edit Item Catalog
Answer: A

NEW QUESTION: 2
You have configured MPLS and RSVP in your network using all of the Junos defaults. You established an LSP in your network which is reporting an up status but no traffic is using it.
Which two statements reflect potential causes for this issue? (Choose two)
A. The LSP egress address does not match the BGP next-hop address
B. No BGP routes are being advertised from the remote neighbor
C. family MPLS was omitted from the router configurations
D. The LSP egress address is a physical interface address
Answer: A,B

NEW QUESTION: 3
What is a potential reason for a job to go from an internal status of READY to FAIL?
A. the script defined in the job does not exist
B. batchman is down
C. netman is down
D. the return code the job returned is not equal to 0
Answer: A

NEW QUESTION: 4
Click the Exhibit button.
The method in the Exhibit must create an HTTP GET connection that works reading both of the following HTTP server response cases:
HTTP server response headers n.1
1 . HTTP/1.1 200 OK
2 . Server: MyServer/1.3.0
3 . Content-Length: 3245
4 . Content-Type: text/html
HTTP server response headers n.2
1 . HTTP/1.1 200 OK
2 . Server: MyServer/1.3.0
3 . Content-Type: text/html
Which two can be used in the fragment of code starting at line 12? (Choose two.)

A. 12. byte[] data = new byte[len];
1 3. int actual = is.read(data);
B. 12. int ch;
1 3. while ((ch = is.read()) != -1) {
1 4. //...
2 0. }
C. 12. int ch;
1 3. while ((ch = is.read()) == -1) {
1 4. //...
2 0. }
D. 12. if (len > 0) {
1 3. byte[] data = new byte[len];
1 4. int actual = is.read(data);
1 5. //...
2 0. } else {
2 1. int ch;
2 2. while ((ch = is.read()) != -1) {
2 3. //...
3 0. }
3 1. }
Answer: B,D

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