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NEW QUESTION: 1
次の表に示すリソースを含むAzureサブスクリプションがあります。

許可されていないリソースタイプのAzureポリシーはRG1に割り当てられ、次のパラメーターを使用します。

RG1では、VM2という名前の新しい仮想を作成し、VM2をVNET1に接続する必要があります。
最初に何をすべきですか？
A. ポリシーからMicrosoft.Network/virtualNetworksを削除します。
B. サブネットをVNET1に追加します。
C. Microsoft.Compute / virtualMachinesをポリシーから削除します。
D. Azure Resource Managerテンプレートを作成します。
Answer: C
Explanation:
Explanation
The Not allowed resource types Azure policy prohibits the deployment of specified resource types. You specify an array of the resource types to block.
Virtual Networks and Virtual Machines are prohibited.
Reference:
https://docs.microsoft.com/en-us/azure/governance/policy/samples/not-allowed-resource-types

NEW QUESTION: 2
どのステートメントはシスコ検出プロトコルを介してお互いに学ぶCiscoデバイスについて真ですか。
A. 各デバイスはマルチキャストアドレス01:00:0C:CC:CC:CCにアドバタイズを定期的に送信します。
B. 各デバイスはネットワークトポロジを構築する中央装置へのアドバタイズを定期的に送信します。
C. 各デバイスはそのARPテーブル内のすべてのIPアドレスにアドバタイズを定期的に送信します。
D. 各デバイスはその近隣のすべての定期的な広告を放送します。
Answer: A

NEW QUESTION: 3
10.0.0.0/24サブネット内の奇数番号のホストから許可される標準のアクセス制御エントリはどれですか。
A. 許可10.0.0.1.0.0.0.0
B. 許可10.0.0.1.0.0.0.254
C. 許可10.0.0.0.0.0.0.1
D. 許可10.0.0.0.255.255.255.254
Answer: B
Explanation:
Explanation
Remember, for the wildcard mask, 1s are I DON'T CARE, and 0s are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum: 0001111 = 31).

The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 000 ) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a "0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all oddnumbered hosts in the 10.0.0.0/24 subnet.

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