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NEW QUESTION: 1
あなたの会社には2つのオフィスがあります。 オフィスはサンフランシスコとロサンゼルスにあります。 各オフィスにはデータセンターがあります。
各データセンターには、インターネットへのローカル接続があります。
Contosoという名前のExchange Server 2016組織を展開し、各データセンターに3台のサーバーをインストールします。
すべてのサーバーは、単一のデータベース可用性グループ（DAG）のメンバーです。 各データセンターは、他のデータセンターに複製する2,000のメールボックスをホストします。
DNSで4つのレコードを作成します。 レコードは、次の表のように構成されています。

次の要件を満たすためには、組織にクライアントアクセスソリューションを推奨する必要があります：
インターネットから接続するときは、すべてのユーザーがWeb上のOutlookの同じ名前空間に接続する必要があります。
1つのデータセンターでインターネットへの接続に失敗すると、すべてのユーザーがインターネットからメールボックスにアクセスできる必要があります。
インターネットから接続する場合、Exchange ActiveSyncへのすべてのユーザー接続は、両方のデータセンターで均等に分散する必要があります。
目標を達成するための最良の推奨は何ですか？ 複数の回答選択肢が目標を達成するかもしれない。 ベストアンサーを選択します。
A. Deploy a hardware-based load balancer to each office and configure all of the internal URLs to use mail.contoso.com.
B. in the San Francisco office, configure the external URLs of the servers to use the internal URLofsfmail.contoso.com. In the Los Angeles office, configure
C. Deploy a hardware-based load balancer to each office and configure all of the external URLs to use mail.contoso.com.
D. in the San Francisco office, configure the internal URLs of the servers to use the internal URLofsfmail.contoso.com. In the Los Angeles office, configure
Answer: C

NEW QUESTION: 2
Your company is designing its public network. The network will use an IPv4 range of 131.107.40.0/22. The network must be configured as shown in the following exhibit.

You need to configure subnets for each segment.
Which network addresses should you assign?
A. Segment A: 131.107.40.128/23 Segment B: 131.107.43.0/24 Segment C: 131.107.44.0/25 Segment D: 131.107.44.128/27
B. Segment A: 131.107.40.0/23 Segment B: 131.107.41.0/24 Segment C: 131.107.41.128/25 Segment D: 131.107.43.0/27
C. Segment A: 131.107.40.0/23 Segment B: 131.107.42.0/24 Segment C: 131.107.43.0/25 Segment D: 131.107.43.128/27
D. Segment A: 131.107.40.0/25 Segment B: 131.107.40.128/26 Segment C: 131.107.43.192/27 Segment D: 131.107.43.224/30
Answer: C
Explanation:
1: The corresponding CIDR notation prefix lenth is /22.
2: The next myltiple of 8 that is greater than 22 is 24. Octet 3 is interesting.
3: 24-22 = 2, so the incremental is 2

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