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NEW QUESTION: 1
You have deployed NSNA on your network and are encrypting all portal traffic. There is currently a user session established to a portal you would like to capture. Which statement about this scenario is true?
A. The portal session could not be captured.
B. The tcpdump could be used to capture the portal session.
C. The ssldump could be used to capture the portal session.
D. The traceroute could be used to capture the portal session.
Answer: A

NEW QUESTION: 2
When comparing ultra high frequency (UHF) passive to high frequency (HF) passive RFID, which of the following statements is MOST accurate? (Select TWO).
A. HF is less susceptible to RF absorbent material and better for long read range applications.
B. UHF is able to operate in highly reflective environments and worse at anti-collision.
C. HF is more susceptible to highly reflective environments and better for close range applications.
D. UHF is more susceptible to RF absorbent material and better for high data rate applications.
Answer: C,D

NEW QUESTION: 3
Welche der folgenden Bedrohungen wird durch die Verwendung der tokenbasierten Authentifizierung verhindert?
A. Passwort-Sniffing-Angriff auf das Netzwerk
B. Denial-of-Service-Angriff über das Netzwerk
C. Man-in-the-Middle-Angriff auf den Client
D. Sitzungsabhörangriff auf das Netzwerk
Answer: A

NEW QUESTION: 4

Refer to the exhibit. Which address and mask combination represents a summary of the routes learned by EIGRP?
A. 192.168.25.0 255.255.255.252
B. 192.168.25.0 255.255.255.240
C. 192.168.25.16 255.255.255.240
D. 192.168.25.16 255.255.255.252
E. 192.168.25.28 255.255.255.240
F. 192.168.25.28 255.255.255.240
Answer: C
Explanation:
The binary version of 20 is 10100.
The binary version of 16 is 10000.
The binary version of 24 is 11000.
The binary version of 28 is 11100.
The subnet mask is /28. The mask is 255.255.255.240.
Note:
From the output above, EIGRP learned 4 routes and we need to find out the summary of them: +
192.168.25.16+ 192.168.25.20+ 192.168.25.24+ 192.168.25.28
-> The increment should bE. 28 - 16 = 12 but 12 is not an exponentiation of 2 so we must choose
16 (24). Therefore the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) =
255.255.255.240 So the best answer should be 192.168.25.16 255.255.255.240

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